Puzzle 47

Find the error in this mathematical conundrum. Answer Saturday.

1=1 [To start]
a=b [Got it?]
a•a=b•a [Both sides multiplied by a]
a^2=ab [Which is]
a^2-b^2=ab-b^2 [Subtraction axiom with b^2]
(a+b)(a-b)=b(a-b) [Factored]
(a+b)(a-b)/(a-b)=b(a-b)/(a-b) [Divide both sides by (a-b)]
a+b=b [Which is]
b+b=b [Unnecessary step but shows the result easier]
2b=b [Which is]
2=1 [Equals]

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One Response to Puzzle 47

  1. James says:

    (a+b)(a-b)/(a-b)=b(a-b)/(a-b) [Divide both sides by (a-b)]

    Lets fill this in knowing that x(any number but I chose 1)=a=b

    (x+x)(x-x)/(x-x)=x(x-x)/(x-x)

    Lets solve those parentheses and what do we have here!

    (2x)0/0=1(0/0)

    Anyone knows you cant divide by 0 (Even 0/0 as it causes some problems with logic) Making this incorrect and you now see where we get the 2x from.

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